60=-4x^2-33x+3

Solution for 60=-4x^2-33x+3 equation:

60=-4x^2-33x+3

We move all terms to the left:

60-(-4x^2-33x+3)=0

We get rid of parentheses

4x^2+33x-3+60=0

We add all the numbers together, and all the variables

4x^2+33x+57=0

a = 4; b = 33; c = +57;
Δ = b2-4ac
Δ = 332-4·4·57
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{177}}{2*4}=\frac{-33-\sqrt{177}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{177}}{2*4}=\frac{-33+\sqrt{177}}{8}
$